If it's not what You are looking for type in the equation solver your own equation and let us solve it.
6x^2+5x=54
We move all terms to the left:
6x^2+5x-(54)=0
a = 6; b = 5; c = -54;
Δ = b2-4ac
Δ = 52-4·6·(-54)
Δ = 1321
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(5)-\sqrt{1321}}{2*6}=\frac{-5-\sqrt{1321}}{12} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(5)+\sqrt{1321}}{2*6}=\frac{-5+\sqrt{1321}}{12} $
| 8y-3-5y=42 | | 44x-45=x/3 | | 6x-4-3x=14 | | 7a=3/14 | | 1x-3=10 | | 3x+11=5x−1 | | 2x+5+15x+5=180 | | ((70=14-8)/2)x12 | | 3*(x−1)=2*(x−4) | | 9*(x−1)=72 | | 3b+12=5b-2 | | 12+6x=6+5(x-2) | | 9n=42 | | 3⋅(x+1)=2⋅(x+6)= | | 2(n-3)=2×2n | | -3y-4=-21 | | 44+x=133 | | 6-5x=12-2x | | -2x+3=11-6x6 | | 9x^2+3x-10=0 | | -m+(3m-6m)=-8-15 | | F(x)=x2-5x2+4 | | 3r^2=14-8 | | 4=9-11b | | x^2+10x-630=0 | | 3·(x-2)+1=0,5x+2·(x+2) | | 3·(x-2)+1=0.1x+2·(x+2) | | 3·(x-2)+1=1/2x+2·(x+2) | | f(X)=X²-6X+2 | | 2x-3=3-x | | (x-3)^2018+(x-2)^2018=0 | | 2(x^2+6)+5x=-9x-8 |